Some other comment in this discussion claims that if you nudged the total count integer +-1 you'll never hit 52.20000000% exactly hinting at the possibility that they choose 52.2% exactly, then computed the total counts which would be a non-integer and then just rounded that.
Once re-computing the percentage from that number you end up with the slightly less round-looking 51.1999971%.
Yes, but the comparison is not to "any random set of numbers" it's "all other random sets of numbers"
The candidate got 52.200000% of the vote instead of any other percentage, not another specific percentage.